Solve the equation on the interval 0 ≤ θ 2π. 3√2 cos θ + 2 = - 1 Recent Visits Solve the equation on the interval 0 ≤ θ 2π. Use a calculator to solve the equation on the
So now that we have our solutions of this, we have to solve them in the context of [0, 2π). First, u 1: Solve cos (x)=-1/2, 0≤x2π. Take the arccos to get x=arccos (-1/2)=2π/3 and
Step 1: The equation is on the interval . Using formula . Step 2: then, general solution of sine function is , where is any integer. Take . Take . Take . The solutions required on
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