Best of all, 2nd order differential equation non homogeneous is free to use, so there's no reason not to give it a try!
The second definition — and the one which you'll see much more often—states that a differential equation (of any order) is homogeneous if once all the terms involving the unknown function
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The answer to the equation is 4.
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Now that we have both components, y h and y p, let’s complete the general solution of our second order non-homogeneous differential equation is: y h = C 1 e − x + C 2 e − 5 x y p = 4 5 x – 24 5
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